Please Factorise this
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Given Equation is x^6 + 5x^3 + 8
= > x^6 + 6x^3 - x^3 + 8
= > x^6 + 8 - x^3 + 6x^3
= > (x^2)^3 + (2)^3 + (-x)^3 - 3(x^2)(2)(-x)
It is in the form of a^3 + b^3 + c^3 - 3abc = (a + b + c)(a^2 + b^2 + c^2 - ab - bc - ca)
= > (x^2 + 2 - x)[(x^2)^2 + (2)^2 + (-x)^2 - (x)^2 * (2) - (2)(-x) - (-x)(x^2))
= > (x^2 + 2 - x)[(x^4 + 4 + x^2 - 2x^2 + 2x + x^3)
= > (x^2 + 2 - x)[(x^4 + x^3 - x^2 + 2x + 4).
Hope this helps!
= > x^6 + 6x^3 - x^3 + 8
= > x^6 + 8 - x^3 + 6x^3
= > (x^2)^3 + (2)^3 + (-x)^3 - 3(x^2)(2)(-x)
It is in the form of a^3 + b^3 + c^3 - 3abc = (a + b + c)(a^2 + b^2 + c^2 - ab - bc - ca)
= > (x^2 + 2 - x)[(x^2)^2 + (2)^2 + (-x)^2 - (x)^2 * (2) - (2)(-x) - (-x)(x^2))
= > (x^2 + 2 - x)[(x^4 + 4 + x^2 - 2x^2 + 2x + x^3)
= > (x^2 + 2 - x)[(x^4 + x^3 - x^2 + 2x + 4).
Hope this helps!
siddhartharao77:
:-)
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