please factorise this question as soon as possible. With explanation.
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Hope this helps u Please make me as a brainliest
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Given Equation is x^8 - 1
= > (x^4)^2 - (1)^2
= > (x^4 + 1)(x^4 - 1)
= > (x^4 + 1)((x^2)^2 - (1)^2)
= > (x^4 + 1)(x^2 + 1)(x^2 - 1)
= > (x^4 + 1)(x + 1)(x - 1)(x^2 + 1)
Hope this helps!
= > (x^4)^2 - (1)^2
= > (x^4 + 1)(x^4 - 1)
= > (x^4 + 1)((x^2)^2 - (1)^2)
= > (x^4 + 1)(x^2 + 1)(x^2 - 1)
= > (x^4 + 1)(x + 1)(x - 1)(x^2 + 1)
Hope this helps!
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