Question

please factorise this y3 - 27​

Answer 1

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Answer 2

Answer:

We know that,

a³ – b³ = (a – b) (a² + b² + ab)

y3 – 27 = y³ – (3)³

Here, a = y and b = 3

Now, substituting in the above formula, we get

y³ – (3)³ = (y – 3) [y² + y(3) + (3)2]

= (y – 3) (y² + 3y + 9)