Question

please fast...........​

Answer 1

Answer:

The probability will be 1/6

Explanation :

Favorable outcomes for total of at least 10 are

(4,6),(5,5),(5,6),(6,4),(6,5),(6,6)

Number of favorable outcomes = 6

Hence, the probability of getting a total of atleast 10 = 36/6 ​= 1/6

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Answer 2

Answer:

Two dice are rolled

S = {(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)

(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)

let A be the event of getting the sum of the digits on the upper faces is at least 10.

A = {(4,6),(5,5),(5,6),(6,4),(6,5),(6,6)}

n(A) = 6

P(A) = n(A)/n(S)

=6/36

= 1/6