Question

please find answer i will give you a 5star explain please ​

Answer 1

Answer:

Given that ,ABD= 104°

BCD= 65°

BAD= 3 DBA

BD is perpendicular to AC

So that ,BDA + BDC= 180°

104° + BDC= 180°

=>BDC = 180°-104°= 76°

=>BDC= 76°

In triangle BDC, Sum of three angles is 180°

BDC + BCD + DBC = 180°

76°+65°+DBC = 180°

DBC = 180°-76°-65°

=> DBC = 39°

From the question, it is given that

BAD= 3DBA

Let BAD = x

then x = 3x

According to angle sum property of ABC triangle,

BAD + ACB + ABC = 180

= > 3X + 65 + DBA + DBC = 180

= > 3X + 65 + X + 39 = 180

=> 4X + 104 = 180

=> X = 76/4

=> X = 19°( BAD)

=> 3X = 19×3= 57°(DBA)

Hope it will help you ✌️