Math, asked by dipshikhadas, 1 year ago

please find the answer

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Answered by adee1729
1
let PQRS be a quadrilateral and let A and B be the length of the diagonals, then

area of the ∆PQS=1/2×A×B/2,


area of the ∆QRS= 1/2×A/2×B,

therefore

area of the quadrilateral=area of ∆PQS+area of ∆QRS,

area of quadrilateral=1/2×A×B/2 + 1/2×A/2×B,

=AB/4 + AB/4,

=(AB+AB)/4,

=2AB/4,
then
area of the quadrilateral=1/2 × A × B

Answered by Chaitanya111178
0
hi deepika porida my name chaitanya durga prasad i am from melliaputti do you remember me if yes please send a comment but sorry i cant give you a answer
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