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question no. (2):
length of soccer field
= (3x^2 + 2x + 5) feet
breadth of soccer field
= 4x^2y feet
area = length × breadth
= (3x^2 + 2x + 5) × ( 4x^2y )
= 12x^4y + 8x^3y + 20x^2y feet^2
question (1):
length = 3xy inches
width = (3x^2 + 6x + 10 )
area = length × width
area = 3xy × ( 3x^2 + 6x + 10 )
= (9x^3y + 18x^2y + 30xy ) inches^2
length of soccer field
= (3x^2 + 2x + 5) feet
breadth of soccer field
= 4x^2y feet
area = length × breadth
= (3x^2 + 2x + 5) × ( 4x^2y )
= 12x^4y + 8x^3y + 20x^2y feet^2
question (1):
length = 3xy inches
width = (3x^2 + 6x + 10 )
area = length × width
area = 3xy × ( 3x^2 + 6x + 10 )
= (9x^3y + 18x^2y + 30xy ) inches^2
sdhnfamily:
You are great
Answered by
4
1.
Given Dimensions:
⇒ Length = 3xy
⇒ Breadth = 3x² + 6x + 10
We know that Area of rectangle = length * breadth
⇒ (3xy)(3x² + 6x + 10)
⇒ 9x³y + 18x²y + 30xy inches².
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2.
Given Dimensions are:
⇒ Length = 4x²y.
⇒ Breadth = (3x² + 2x + 5).
We know that Area = Length * Breadth
⇒ 4x²y(3x² + 2x + 5)
⇒ 12x⁴y + 8x³y + 20x²y Sq.feet.
Hope this helps!
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