Please find the answer to this ASAP
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Answer:
Angle AMD = 90°
Step-by-step explanation:
Consider ∆ AMB ,
AM is the hypotenuse
BM is the base = 4 cm
AB is the Altitude = 6 cm
AM^2 = AB^2 + BM^2
AM ^2 = 6^2 + 4^2
AM ^2 = 36+16
AM ^2 = 52
AM = 7.2 cm
Now consider ∆ MCD ,
MD is the hypotenuse
CD is the Altitude = 2 cm
MC is the base = 3 cm
MD^2 = CD^2+ MC^2
MD^2 =2^2 + 3^2
MD^2 =4+9
MD ^2= 13
MD = 3.6 cm
7.2 ^2 + 3.6^2
51.84 + 12.96
= 64.8
√64.8=8.04
~ 8
Angle AMD = 90°
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