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1
Let angle c be x°
.°.angle d =x°
angle a =2x°
angle b=2x°
A T Q
2x+2x+x+x=360
=>6x=360
=>x=360/6=60
.°.The angles are =120°,120°60°and
60°
.°.angle d =x°
angle a =2x°
angle b=2x°
A T Q
2x+2x+x+x=360
=>6x=360
=>x=360/6=60
.°.The angles are =120°,120°60°and
60°
Answered by
0
all the angles in a quadrilateral equals 360°
a+b+c+d=360°
a=b and c=d=a/2
thus, a+a+a/2+a/2=360°
3a=360°
a=120°=b
c=d=120/2=60°
a+b+c+d=360°
a=b and c=d=a/2
thus, a+a+a/2+a/2=360°
3a=360°
a=120°=b
c=d=120/2=60°
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