please find the product of this (5-2d-d²)(3-2d)
Answers
Answered by
35
Here is given, (5-2d-d^2)(3-2d)
= (15-6d-3d^2-10d+4d^2+2d^3)
= (2d^3 +4d^2-3d^2-6d-10d+15)
= (2d^3+d^2 - 16d+15)
Hope it will help you
Thanks for watching the answer.
= (15-6d-3d^2-10d+4d^2+2d^3)
= (2d^3 +4d^2-3d^2-6d-10d+15)
= (2d^3+d^2 - 16d+15)
Hope it will help you
Thanks for watching the answer.
aman9340:
Hope it was correct
Answered by
12
Hii..
Here is ur answer :-
******************************
******************************
(5-2d-d) (3-2d)
3(5-2d-d) - 2d(5-2d-d)
= 15-6d-3d+10d+4d^2+2d^2
= 15-9d+10d+4d^2+2d^2
= 15+d+4d^2+2d^2
This is ur answer.
Hope it helps u!!
Here is ur answer :-
******************************
******************************
(5-2d-d) (3-2d)
3(5-2d-d) - 2d(5-2d-d)
= 15-6d-3d+10d+4d^2+2d^2
= 15-9d+10d+4d^2+2d^2
= 15+d+4d^2+2d^2
This is ur answer.
Hope it helps u!!
Similar questions