please find the value of the given equation
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given polynomial p(s)=3s²-6s+4 α+β=-(-6)/3=2 α.β=4/3
α/β+β/α=α²+β²/αβ=(α+β)²-2αβ/αβ=2²-2.4/3∕(4/3) =12(1/α+1/β)=2(α+β)/αβ=2/(4/3)=3/23αβ=3*4/3=4
now you can calculate
(α/β+β/α)+2(1/α+1/β)+3αβ=just find sum for above three values
α/β+β/α=α²+β²/αβ=(α+β)²-2αβ/αβ=2²-2.4/3∕(4/3) =12(1/α+1/β)=2(α+β)/αβ=2/(4/3)=3/23αβ=3*4/3=4
now you can calculate
(α/β+β/α)+2(1/α+1/β)+3αβ=just find sum for above three values
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hope i have helped you ??
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solution is in the pic
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