Question

please find this question for class 10 maths ​

Answer 1

Answer:

$13 \frac{5}{3}$

is your answer

Step-by-step explanation:

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Answer 2

Answer:

sec theeta=13/12

so , tan theeta =√(sec^2theeta-1)

=√{(13/12)^2-1}

=√(169/144-1)

=√(169-144)/144

=√25/144

=5/12

so , tan theeta=5/12

so , cot theeta=12/5

sec theeta=13/12

cos theeta =12/13

sin theeta=√(1-cos^2 theeta)

=√(1-12/13^2)

=√(1-144/169)

=√(169-144)/169

=√25/169

=5/13

so , sin theeta =5/13

so , cosec theeta =13/5