Question

please Frend's solve it ​

Answer 1

Step-by-step explanation:

First consider two

number a = 693 and b = 567

693=587*1+126

( are not equal to

567+126*4+63

( not equal to 0)

126=63*+*2+0

(equal to 0)

stop here

HCF of 693, 597=63

Now find HCF of (441,63)

where c =441 and

assume d = 63

Again apply Euclid's division lemma c =dq+r

441=63*7+0

(equal to 0)

Therefore HCF of 441 and 63 is 63

Therefore HCF of 441,567 and 693 is 63

Hope you understand