Question

please friend solve the above question ,,,,,,,it's too urgent....

Answer 1

7sin²@+3cos²@= 3sin²@+3cos²@+4sin²@=4

3(sin²@+cos²@)+4sin²@=4

3(1)+4sin²@=4

4sin²@=4-3

Sin²@=1/4

Sin@=1/2

Cos@= √1-sin²@=√1-1/4=√3/2

tan@= sin@/cos@= 1/2×2/√3

= 1/√3...ans

Answer 2

Hi there!
Here's the answer:

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Taking theta as x

Given,
7Sin²x + 3cos²x = 4
=> 4sin²x + 3sin²x + 3cos²x = 4
=> 4sin²x + 3(sin²x + cos²x) = 4

°•° sin²x + cos²x = 1
=> 4sin²x +3(1) = 4
=> 4 sin²x = 1
=> sin²x = 1/4
=> sin x = 1/√2
=> sin x = Sin 30°

•°• x = 30°


L.H.S =
tan x = tan 30°
= Sin 30°/Cos 30°
= (1 /2)/(√3/2)
= (1/√3)
= R.H.S

Hence proved.

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Hope it helps