Please friends help me to find the answer of the question in that figure.
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angle CAO= angle OAB
here
angle BOD=90° so
angle DBA= BOA
it's mean that rays CA and BD is perpendicular to line AB
.
so CA is parallel to the reflected ray BD
here
angle BOD=90° so
angle DBA= BOA
it's mean that rays CA and BD is perpendicular to line AB
.
so CA is parallel to the reflected ray BD
RudranilAdhikari:
Bro can you say me from where you get BOD=90
Answered by
0
Angle DBO = Angle ABO
Angle CAO = Angle BAO
(Angle of incidence = Angle of reflection)
In triangle AOB,
Angle BOA + Angle OBA + Angle OAB = 180 ( Angle Sum Property)
90 + Angle OBA + Angle OAB = 180
Angle OBA + Angle OAB = 90.
Multiply both sides by 2
Therefore,
2OBA + 2OAB = 2*90
Angle ABD + Angle BAC = 180
Therefore, BD||AC as these angles form co-interior angles and BA as transversal.
Angle CAO = Angle BAO
(Angle of incidence = Angle of reflection)
In triangle AOB,
Angle BOA + Angle OBA + Angle OAB = 180 ( Angle Sum Property)
90 + Angle OBA + Angle OAB = 180
Angle OBA + Angle OAB = 90.
Multiply both sides by 2
Therefore,
2OBA + 2OAB = 2*90
Angle ABD + Angle BAC = 180
Therefore, BD||AC as these angles form co-interior angles and BA as transversal.
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