Question

please give a answer don't answer useless things

Answer 1

Answer:

so, sin²A-(1-cosA)²/(1-cosA)sinA

⇒2cosA/(1-cosA)sinA

cos²A-(1-sinA)²/(1-sinA)cosA

⇒2sinA/(1-sinA)cosA

multiplying these two we get,

4sinAcosA/(cosA-cosAsinA)(sinA-cosAsinA)

solve this to get answer

HOPE IT HELPS