Math, asked by tigerlionking, 5 months ago

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Answered by ravindrabansod26
11

Question:-

If \frac{ 1 + 2 + 3 + 4 + ....... upto \: n \: term}{ 1.2 + 2.3 + 3.4 + ..... upto \: n \: term} = 0.03

to find n

Answer:-

\frac{ 1 + 2 + 3 + 4 + ....... upto \: n \: term}{ 1.2 + 2.3 + 3.4 + ..... upto \: n \: term} = 0.03

⇒ ∑n / ∑n ( n+1 ) = 0.03

\frac{\frac{n(n+1)}{2} }{\frac{n(n+1)(2n+1)}{6} + \frac{n(n+1)}{2}  } = 0.03

\frac{1}{\frac{2n + 1}{3} + 1} = 0.03

\frac{1}{2n + 4 } = 0.01

2n+4 = 100

2n = 100 - 4 = 96

n = 46

hence the value of n = 46

thank you.......

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