Math, asked by PerfectOnBrainly, 9 months ago

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Answered by hrn21agmailcom
1

Answer:

solved

Step-by-step explanation:

R = { ( a, b } / ( a, b ) € Q ; a - b € Z }

now take....

a = 1/3 ; b = -2/3 ; c = -5/3

(a) since.....

1/3 - 1/3 = 0 € Z

hence...

( a, a ) € R

(b) since....

1/3 - (-2/3) = 1 € Z and (-2/3) - 1/3 = -1 €Z

hence.....

( a, b ) € R & ( b, a ) € R

(c) since -2/3 - (-5/3) = 1 € Z

( b, c) € R

now....since..

1/3 - ( -5/3 ) = 2 € Z

( a, c ) € R

hence....

( a, b ) € R & ( b, c ) € R then ( a, c ) € R

Answered by Abhinavraj9801
1

Step-by-step explanation:

R ((a,b)/(a,b) €Q ; a-b €Z

Now,

a=1/3 ; b=2/3 ; c = 5/3

since....

1/3 - 1/3 = 0€Z

Hence

( a,a ) €R

( b ) since ....

1/3-(-2/3) = 1€Z and ( -2/3 )-1/3 = -1€Z

Hence.......

( a,b) €R & ( b , a ) €R

( c ) since -2/3 - ( -5/3 ) = 1€Z

( b,c ) €R

Now then,

1/3 - ( -5/3 ) =2€Z

( a,c) €R

Therefore; (a,b) €R & ( b,c) €R and ( a,c ) €R

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