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Lengths of tangents to a circle from an external point are equal.
This means,
From point P, PA=PS=4 cm
From point R, SR=RC=5 cm
From point Q, CQ=QA=6 cm
Perimeter = PA +AQ+QC+CR+SR+PS.
=
4+6+6+5+5+4 = 2(4+5+6) =2*15= 30cm
Perimeter of ∆PQR is 30 cm
This means,
From point P, PA=PS=4 cm
From point R, SR=RC=5 cm
From point Q, CQ=QA=6 cm
Perimeter = PA +AQ+QC+CR+SR+PS.
=
4+6+6+5+5+4 = 2(4+5+6) =2*15= 30cm
Perimeter of ∆PQR is 30 cm
Answered by
2
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