Question

Please give correct ans !!!

Answer 1

you answer with this attachment .



hope it helps!!!


thanks

Answer 2

HELLO DEAR,

we know that:-

(a³-b³) =(a-b) (a²+b²+ab)
and

$\frac{ {x}^{m} }{ {x}^{n} } = {x}^{m - n}$

now the solution is



${( \frac{ {x}^{a} }{ {x}^{b} }) }^{ {a}^{2} + {b}^{2} + ab} \times {( \frac{ {x}^{b} }{ {x}^{c} }) }^{ {b}^{2} + {c}^{2} + cb} \times {( \frac{ {x}^{c} }{ {x}^{a} }) }^{ {c}^{2} + {a}^{2} + ac} \\ \\ = {x}^{(a - b)( {a}^{2} + {b}^{2} + ab)} \times {x}^{(b - c)( {b}^{2} + {c}^{2} + bc) } \times {x}^{(c - a)( {c}^{2} + {a}^{2} + ac) } \\ \\ = {x}^{( {a}^{3} - {b}^{3} )} \times {x}^{( {b}^{3} - {c }^{3} )} \times {x}^{( {c}^{3} - {a}^{3} )} \\ \\ = \frac{ {x}^{ {a}^{3} } }{ {x}^{ {b}^{3} } } \times \frac{ {x}^{ {b}^{3} } }{ {x}^{ {c}^{3} } } \times \frac{ {x}^{ {c}^{3} } }{ {x}^{ {a}^{3} } } = 1 \\ \\.................hence........... \\ \\ {( \frac{ {x}^{a} }{ {x}^{b} }) }^{ {a}^{2} + {b}^{2} + ab} \times {( \frac{ {x}^{b} }{ {x}^{c} }) }^{ {b}^{2} + {c}^{2} + cb} \times {( \frac{ {x}^{c} }{ {x}^{a} }) }^{ {c}^{2} + {a}^{2} + ac} = 1$
I HOPE ITS HELP YOU DEAR,
THANKS ☺️☺️☺️