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Step-by-step explanation:
Given :-
Angle X of ∆XYZ cuts YZ at W . The circle whose centre is W and radius XY cuts and XY at P and Q respectively .
To prove :-
XP = XQ
Construction :-
Draw WT perpendicular XP and WB perpendicular XT .
Solution :-
∆ WXA = ∆ WXB [ By AAS congruence ]
XA = XB [ CPCT ]
2XA = 2XB
XP = XQ
[ Perpendicular from the centre of a circle to the chord bisect it . ]
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