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Given equation is y = - x^2.
i.e., for all +ve and -ve values of x, values of y is -ve only.
Therefore equation lies in 3rd and 4th quadrant. Option: (3)
i.e., for all +ve and -ve values of x, values of y is -ve only.
Therefore equation lies in 3rd and 4th quadrant. Option: (3)
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y+x^2=0
x^2=-y
so all the value of x will be +ve but the values of y will be negative
the condition where x is positive and y is negative lies in the 1st and 4th quadrant only.
So the answer is (4)Q4,Q1.
Hope it helped
Please mark it as brainliest.
x^2=-y
so all the value of x will be +ve but the values of y will be negative
the condition where x is positive and y is negative lies in the 1st and 4th quadrant only.
So the answer is (4)Q4,Q1.
Hope it helped
Please mark it as brainliest.
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