Math, asked by rishikadeshpande06, 9 months ago

please give full explanation
and fast please​

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Answered by nalanagulajagadeesh
1

Answer:

given, A Force of 4N acts on a body of mass 2kg for 5sec,

we know that F=m.a,

=>acceleration,a =F/m=4/2=2m/s^2.

1)we know that acceleration means rate of change of velocity.

given body starts from rest,so, initial velocity is equal to zero,

a=dv/dt=(v2-v1)/t,

=>2=(v2-0)/4,

=>V2=8m/s

2)distance travelled in 10secs after force is acting,

we know that ,S =Ut+1/2(at^2)

=>S=0+1/2(2*10^2),

=>S=100mtr

Answered by vkpathak2671
2

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I don't no your question

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