Please give full solution of Q.4
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I have given figure for your help now your answer has given below :-
Given : PQ||ST, Lpqr = 110° and Lrst = 130°.
To find : Lqrs = ?
Construction : Draw a line LM||PQ||ST.
Solve : Since PQ||LR,
Lpqr + Llrq = 180° (co-int)
110° + Llrq = 180°
Llrq = 180° - 110°
Llrq = 70°
Again, ST||RM,
Ltsr + Lsrm = 180° (co-int)
130° + Lsrm = 180
Lsrm = 180° - 130°
Lsrm = 50°.
LRM is a straight line
Lqrs = 180° - ( Llrq + Lsrm)
Lqrs = 180° - ( 70° +50°)
Lqrs = 180° - 120°
Lqrs = 60°
●Completed●
_____________
●●●●●●●●●●●●●●●●●●●●●●●●●●
●●●●●●●●●●●●●●●●●●●●●●●●●●
◆Thanks
◆ Best of Luck
◆ Mark it as Brian list.
◆ Bye
●●●●●●●●●●●●●
Given : PQ||ST, Lpqr = 110° and Lrst = 130°.
To find : Lqrs = ?
Construction : Draw a line LM||PQ||ST.
Solve : Since PQ||LR,
Lpqr + Llrq = 180° (co-int)
110° + Llrq = 180°
Llrq = 180° - 110°
Llrq = 70°
Again, ST||RM,
Ltsr + Lsrm = 180° (co-int)
130° + Lsrm = 180
Lsrm = 180° - 130°
Lsrm = 50°.
LRM is a straight line
Lqrs = 180° - ( Llrq + Lsrm)
Lqrs = 180° - ( 70° +50°)
Lqrs = 180° - 120°
Lqrs = 60°
●Completed●
_____________
●●●●●●●●●●●●●●●●●●●●●●●●●●
●●●●●●●●●●●●●●●●●●●●●●●●●●
◆Thanks
◆ Best of Luck
◆ Mark it as Brian list.
◆ Bye
●●●●●●●●●●●●●
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chinmay82:
Thank you so much
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