Math, asked by sandy72, 1 year ago

please give me a step by step answer of it

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InfinityMS: Hey once again will you type this question here
InfinityMS: I m not getting your operational symbols
sandy72: ok

Answers

Answered by snehitha2
11
Let's solve first 7+√5/7-√5

→ (7+√5)/(7-√5)×(7+√5)/(7+√5)

→ (7+√5)(7+√5)/(7-√5)(7+√5)

→ (7+√5)²/(7²-√5²)

→ {7²+√5²+2(7)(√5)}/(49-5)

→ (49+5+14√5)/44

→ (54+14√5)/44


Now solve 7-√5/7+√5

→ (7-√5)/(7+√5)×(7-√5)/(7-√5)

→ (7-√5)²/(7+√5)(7-√5)

→ {7²+√5²-2(7)(√5)}/(7²-√5²)

→ (49+5-14√5)/(49-5)

→ (54-14√5)/44

Now,

7+√5/7-√5 - 7-√5/7+√5

→ (54+14√5)/44 - (54-14√5)/44

→ (54+14√5-54+14√5)/44

→ 28√5/44

→14√5/22

→ 7√5/11

→ 7√5 × 1/11

= a +7√5b

By comparing we get,

a = 0 and b = 1/11

Hope it helps

sandy72: thank you sooooooooooooooo much!
Answered by ImpressAgreeable4985
0

Answer:

Mark it as brainlist answer

Step-by-step explanation:

given,

14+6

5

=

14+2×3

5

=

9+5+2×3

5

=

9+2×3

5

+5

=

(3)

2

+2×3

5

+(

5

)

2

=

(3+

5

)

2

=3+

5

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