Question

please give me answer ​

Answer 1

Solution

(I)

from the quadrilateral DXBY....

DY=(1/2)DC

BX=(1/2)AB

now..as...AB=DC

therefore...DY=BX...and also BX||DY.....

therefore...

DXBY is a parallelogram..(proved)

so..DX||BY

(ii)

from the quadrilateral AXCY....

CY=(1/2)DC

AX=(1/2)AB

X=(1/2)ABnow..as...AB=DC

X=(1/2)ABnow..as...AB=DCtherefore...CY=AX...and also AX||CY.....

Y.....therefore...

AXCY is a parallelogram.

so..AY||CX

therefore

for the quadrilateral....PXQY...

PY||XQ( as,,AY||CX)

and..PX||YQ (as,,DX||BY)

therefore...PXQY is a parallelogram..(proved)...

hope this helps u.....