Math, asked by kumarsonu2, 11 months ago

please give me answer​

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Answers

Answered by Anonymous
1

Step-by-step explanation:

Solution :-

At 12 noon, the temperature = 14° C above zero

The temperature is decreasing at 2° C per hour

8° C below zero = - 6° C

So, total fall in temperature from 14° C to 0° C and from 0° C to - 6° C = 20° C

Since the temperature falls 2° C in every one hour.

Therefore, to decrease 20° C, time taken = 20/2

= 10 hours

Present time is 12 noon so, the time when the temperature is - 6° C

= 12 noon + 10hours

So, The time at which the temperature will be - 6° C = 10 PM

At 9 PM, the temperature is - 6° C, the temperature at 12 midnight will be = 

(- 6° C) + (- 2° C × 3 hours)

= (- 6° C) + (- 6° C)

= - 12° C

So, at 12 midnight the temperature will be - 12° C.

Answer.

Answered by JayaramJR07
2

Answer:

If temperature deacese at rate of 2 degrees per hour

Asked for 6 degrees below zero

That is = - 6 degrees

Total decrease in temperature

= from 14 degrees to - 6 degrees

=20 degrees

2 degrees ====> 1hour

20 degrees ====> 10 hours

So 12 noon +10 hours

10 pm

10 pm is your 1st answer

At midnight

Time = 12 am

Increase in time period

= 12 noon to 12 midnight

=12 hours

For 1 hour=====> 2 degrees decreases

12 hours ======>24 degrees decreases

Midnight temp = Present temperature - 24 degrees

14 degrees - 24 degrees

-10 degrees

-10 degrees is your second answer

Hope it may help you

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