Question

The sum of digits of a two digit number is 8. If the digits are reversed, the new number increased by 10 to twice the original number. Find the number.

Answer 1

HEY MATE YOUR ANSWER IS HERE....

LET ONES DIGIT NO BE = X

AND TENS DIGIT NO BE = Y

HENCE NO IS

10 X + Y .....

NOW ACCORDING TO QUESTION...

the sum of the digits of a two-digit numeral is 8.

x + y = 8------------ eq1

If the digits are reversed, the new number increased by 10 to twice the original number.

10y + x = 2( 10x + y ) + 10

10 y + x = 20x + 2y + 10

8y - 19x = 10 ---------- Eq 2

★ now by substitution method ★

from Eq 1

y = 8 - x -------- Eq 3

now put Eq 3 in Eq 2

8( 8 - x ) - 19 x = 10

64 - 8x - 19x = 10

28 x = 54

★ x = 2 ★

put the value of x in Eq 3

y = 8 - 2

★ y = 6 ★

Hence the number is 26

THANKS FOR YOUR QUESTION HOPE IT HELPS

★ KEEP SMILING ☺️✌️ ★