Question

please give me answer ​

Answer 1

First of all , we need to look very carefully at the Distance vs Time graph :

We can see that the linear line for Thief (T) started initially from 40 m position and then got intersected by the Police Line (P) at 60 m position.

Similarly the Police Line (P) starts from origin and Meets the Thief (T) at 60 m position from origin

Now coming to the Questions:

1) At the start of the motion the thief had been ahead of the police by 40 metre distance because the police was present at origin where as the thief started from 40m position.

2) The police catches the thief at 60 m position from origin by a time of 3 seconds

Answer 2

AnSwEr

${\tt{\red{\underline{Given}}}}$

• A distance time graph
• Where motion is Given

${\sf{\green{\underline{To\:find}}}}$

• How much T ahead of p when the motion starts
• when and what will p catch T

${\sf{\pink{\underline{Explanation}}}}$

From this graph we conclude that .

• Theif start their motion from 40 m position
• And Police which travel uniform motion from this graph.
• They cover from origin

1. When motion start t=0 position of Thief is 40m And Position of police is 0m

• 40 m t ahead of p when the Motion start

2).

• Here the graph intersect at t point
• means the position of T and P is same at this time
• After three second police catch the theif on t position