Math, asked by naveenkanojia037, 1 month ago

please give me answer​

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Answers

Answered by varadad25
7

Question:

The total surface area of a cone of radius r / 2 and height 2h is:

i) \displaystyle{\sf\:2\:\pi\:r\:(\:h\:+\:r\:)}

ii) \displaystyle{\sf\:\pi\:r\:\left(\:h\:+\:\dfrac{r}{4}\:\right)}

iii) \displaystyle{\sf\:\pi\:r\:(\:h\:+\:r\:)}

iv) \displaystyle{\sf\:2\:\pi\:r\:h}

Answer:

The total surface area of the cone would be

\displaystyle{\pmb{\sf\:Option\:ii)}\sf\:\pi\:r\:\left(\:h\:+\:\dfrac{r}{4}\:\right)}

Step-by-step-explanation:

We have given that,

  • Radius of cone ( R ) = r / 2

  • Slant height of cone ( l ) = 2h

We know that,

\displaystyle{\boxed{\pink{\sf\:Total\:surface\:area\:of\:cone\:=\:\pi\:R\:(\:R\:+\:l\:)\:}}}

\displaystyle{\implies\sf\:TSA_{cone}\:=\:\pi\:.\:\dfrac{r}{2}\:\left(\:\dfrac{r}{2}\:+\:2h\:\right)}

\displaystyle{\implies\sf\:TSA_{cone}\:=\:\dfrac{\pi\:r}{2}\:\left(\:\dfrac{r\:+\:4h}{2}\:\right)}

\displaystyle{\implies\sf\:TSA_{cone}\:=\:\dfrac{\pi\:r\:(\:r\:+\:4h\:)}{2\:\times\:2}}

\displaystyle{\implies\sf\:TSA_{cone}\:=\:\dfrac{\pi\:r\:(\:r\:+\:4h\:)}{4}}

\displaystyle{\implies\sf\:TSA_{cone}\:=\:\pi\:r\:\left(\:\dfrac{4h\:+\:r}{4}\:\right)}

\displaystyle{\implies\sf\:TSA_{cone}\:=\:\pi\:r\:\left(\:\dfrac{\cancel{4}\:h}{\cancel{4}}\:+\:\dfrac{r}{4}\:\right)}

\displaystyle{\implies\:\underline{\boxed{\red{\sf\:TSA_{cone}\:=\:\pi\:r\:\left(\:h\:+\:\dfrac{r}{4}\:\right)\:}}}}

The total surface area of the cone would be

\displaystyle{\boxed{\red{\sf\:\pi\:r\:\left(\:h\:+\:\dfrac{r}{4}\:\right)}}}

Answered by anshu24497
10

Answer :

\displaystyle{\sf\:Option\:ii)}\sf\:{\pi\:r\:\left(\:h\:+\:\dfrac{r}{4}\:\right)\:\:}

Step-by-step-explanation :

Given that -

⭑Radius of cone (R) = r/2

⭑Slant height of cone (l) = 2h

We know that -

\displaystyle{\boxed{\sf\:Total\:surface\:area\:of\:cone\:=\:\pi\:R\:(\:R\:+\:l\:)\:}}

\displaystyle{\sf\:=\:\pi\:.\:\dfrac{r}{2}\:\left(\:\dfrac{r}{2}\:+\:2h\:\right)}

\displaystyle{\sf\:=\:\dfrac{\pi\:r}{2}\:\left(\:\dfrac{r\:+\:4h}{2}\:\right)}

\displaystyle{\sf\:=\:\dfrac{\pi\:r\:(\:r\:+\:4h\:)}{2\:\times\:2}}

\displaystyle{\sf\:=\:\dfrac{\pi\:r\:(\:r\:+\:4h\:)}{4}}

\displaystyle{\sf\:=\:\pi\:r\:\left(\:\dfrac{4h\:+\:r}{4}\:\right)}

\displaystyle{\sf\:=\:\pi\:r\:\left(\:\dfrac{\cancel{4}\:h}{\cancel{4}}\:+\:\dfrac{r}{4}\:\right)}

\displaystyle{\underline{\boxed{\sf\:=\:\pi\:r\:\left(\:h\:+\:\dfrac{r}{4}\:\right)\:}}}

∴ The total surface area of the cone would be

\displaystyle{\boxed{\red{\sf\:\pi\:r\:\left(\:h\:+\:\dfrac{r}{4}\:\right)}}}

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