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Since AD parallel BC..
so angle 1 equal to angle 2 (alternate interior angle)
angle 1 = angle 2
So, side AB = side AC (side opposite to equal angles are equal)
so angle 1 equal to angle 2 (alternate interior angle)
angle 1 = angle 2
So, side AB = side AC (side opposite to equal angles are equal)
navneet123098:
a³+b³+c³-3abc= 6(a+b+c)(a+b+c)-ab-bc-ac
take - common and puttinɡ the values
a³+b³+c³-3abc= 6×6×6-8
a³+b³+c³-3abc= 6×6×6-8 a³+b³+c³-3abc= 208
a³+b³+c³= 208+3abc
a³+b³+c³=208+(-15). a³+b³+c³= 193
thanks
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