Question

please give me answer fast and right ​

Answer 1

Answer:

In ∆ABD & ∆ACD,

Seg AB ≅ AC (given)

< BAD ≅ < DAC (Construction)

Seg AD ≅ AD [Common]

∴ ∆ABD ≅ ∆ACD [SAS rule]

∴ < ABD ≅ < ACD (c.a.c.t)