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Answer:
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Step-by-step explanation:
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Answer:
a) 3:4
b) 6 units
c) 8 units
Step-by-step explanation:
a) Area of first triangle = 1/2 × b × h
= 1/2 × 9 × 5
Area of second triangle = 1/2 × 10 × 6
Ratios of areas of triangles
= Area of first triangle/Area of second triangle
= 3:4
b) MP = MQ + QP = 9+4 = 13
In ∆ MNP -
MN^2 + NP^2 = MP^2 [By Pythagoras theorem]
=> MN^2 = MP^2 - NP^2 (1)
In ∆ MNQ -
MN^2 = MQ^2 + NQ^2 (2)
From (1) and (2)
=> MP^2 - NP^2 = MQ^2 + NQ^2
=> NP^2 = MP^2 - MQ^2 - NQ^2
=> NP^2 = (13)^2 - (9)^2 - NQ^2
=> NP^2 = 169 - 81 - NQ^2
=> NP^2 = 88 - NQ^2 (3)
Now, In ∆ NQP
NP^2 = QP^2 + NQ^2 (4)
From (3) and (4)
=> QP^2 + NQ^2 = 88 - NQ^2
=> (4)^2 - 88 = - NQ^2 - NQ^2
=> 16 - 88 = -2NQ^2
=> NQ^2 = -72/-2
=> NQ = √36 = 6
Hence NQ = 6 units
c) Distance formula = [ (x2-x1)^2 + (y2-y1)^2 ]
= [ (4-2)^2 + (1-3)^2 ]
=> 4 + 4 = 8 units