Question

please give me answer in early questions no 1

Answer 1

since given that

triangle ABC~triangle DEF

then

area(triangle ABC)/area (triangleDEF)=AB^2/DE^2

(we know that the ratio of area of two similar triangle is equal to the ratio of square of their coresponding sides)

then

1/2=4^2 /DE^2

DE^2= 16×2

DE^2=32

DE=

$\sqrt{32}$

then

DE =

$4 \sqrt{2}$

this is your answer......

thanks....