Question

please solve this question.​

Answer 1

Answer:

(1,3)

Step-by-step explanation:

c(x,y)= (m1*x2+m2*x1 / m1+m2), (m1*y2+m2*y1 / m1+m2)

        = (2*4 + 3*-1 / 2+3), (2*-3 + 3*7 / 2 + 3)

         = (8-3 / 5), (-6+21 / 5)

        = (5/5,15/5)

         =(1,3)

∴The point that divides the linesegment in 2:3 ratio is (1,3)

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Answer 2

Answer:

Step-by-step explanation:

Let P (x,y) divide the line joining A(-1,7) and B (4,-3) in ratio 2:3

Now, by applying section formula we have,

X = (m1x2 + m2x1)/(m1 + m2 )

={2*4 +3*(-1)}/ 2+3

= { 8 -3}/5

=5/5

= 1

And for y,

Y=(m1y2 + m2y1)/(m1 + m2 ) } .

= {2(-3) +2(7)/2+3

= {-6+21}/5

=15/5

= 3

Therefore , X=1 and Y= 3.

{ie. P(1,3) option iii}