please give me answers
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Step-by-step explanation:
in ∆PQR and ∆PQS
PQ = PQ. ( COMMON SIDE)
PR= QS. (GIVEN )
<P = <Q. (90°)
THEREFORE. ∆PQR IS CONGRUENT TO ∆PQS BY S.A.S CONGRUENCE
PS = RQ BY C.P.C.T
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Step-by-step explanation:
In triangle RPQ and PQS
angle P = angle Q ------each 90°
side RP = side QS ------- given
side PQ = side QP ------- common side
Therefore
By SAS test
Triangle RPQ = Triangle PQS
side PS = side RQ
corresponding sides of congruent triangles are congruent
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