Math, asked by jduf, 1 year ago

please give me its solution

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Answered by BEJOICE
1

 \cos \theta +  \cos 2\theta =  \cos \theta + 2 { \cos }^{2}  \theta - 1 \\  = 2 { \cos }^{2}   \theta + 2 \cos \theta -  \cos \theta - 1 \\ =  2 \cos \theta( \cos \theta + 1) - ( \cos \theta + 1) \\  = (2 \cos \theta - 1)( \cos \theta + 1) \\ minimum \:  \: value \:  \: for \:  \: this \:  \:  \\ expression \:  \: corresponds \:  \: to \:  \:  \\ minimum \:  \: value \:  \: for \:  \:  \cos \theta \:

minimum \:  \: value \:  \: for \:  \:  \cos \theta \: \: is \:  \:  - 1 \\ therefore \\ minimum \:  \: value \:  \: for \:  \: given \\ expression \:  \: is \:  \: (2 \times  - 1 - 1) \times ( - 1 + 1) \\  = 0 \\ option \:  \: (c)


jduf: but answer is option B
BEJOICE: I tried with calculus and getting same result 0
jduf: ohh
BEJOICE: it may be quoted wrong as option B
BEJOICE: Anyway, I will come back to you if result is different
jduf: you are right... B will not be correct answer
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