Question

please give me maths question​

Answer 1

Step-by-step explanation:

Given,

$1) sec \theta + tan \theta = m$

$2)sec \theta - tan \theta = n$

To Show :-

$m \times n = 1$

Solution :-

We know that :-

$1) {sec}^{2} \theta - {tan}^{2} \theta = 1$

$2) {sec}^{2} \theta - {tan}^{2} \theta = (sec \theta + tan \theta) \times (sec \theta - tan \theta) = 1$

[ Since from , a^2 - b^2 = (a+b)(a - b)

Given,

$sec \theta + tan \theta = m$

$sec \theta - tan \theta = n$

Substituting these values :-

${sec}^{2} \theta - {tan}^{2} \theta = m \times n = 1$

$\implies \: m \times n = 1$

Hence Proved

Know More :-

Trigonometric Identities :-

$1) {sin}^{2} \theta + {cos}^{2} \theta = 1$

$2) {sec}^{2} \theta - {tan}^{2} \theta = 1$

$3) {cosec}^{2 } \theta - {cot}^{2} \theta = 1$

Answer 2

Answer:

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