Question

please give me my answer​

Answer 1

Step-by-step explanation:

$\frac{x + 3}{x - 3} - \frac{x - 3}{x + 3} = 1 - \frac{ {x}^{2} }{ {x}^{2} 9} \frac {1}{p} = x + 1 \\ ( \frac{x + 3}{x - 3} ) - ( \frac{x - 3}{x + 3} ) = 1 \\ x = 3 - 3 = 0 \\ x = 3 + 3 = 6 \\ x = - 9 + 6 \\ x = \frac{3}{3} = x = 1 \\ x + 1$