Question

Please give me only answer.
SERIOUSLY.
Tommorow is my exam​

Answer 1

$\begin{gathered}\qquad\qquad{\underline{\underline{\frak{\pink{Correct \: question \: \;\;:}}}}}\\ \\\end{gathered}$

The two interior opposite angles of an exterior angle of a triangle are 58° and complement of 48. Find the measure of the exterior angle.

$\begin{gathered}\qquad\qquad{\underline{\underline{\frak{\purple{Required\;Answer\;:}}}}}\\ \\\end{gathered}$

Let's Suppose ∠ABC be the interior angle .

Let's suppose ∠ ACD be the exterior angle.

Given that :

The two interior opposite angles of an exterior angle of a triangle are 58° and complement of 48°

To find :

• Measure of exterior angle ?

Solution :

We know that ,

• ● Measure of exterior angle is equal to sum of two interior opposite angle.

Therefore , Meausre of exterior ∠ACD is ,

$\implies ∠ ACD= ∠ABC + ∠BAC$

$\implies ∠ ACD= 58°+48°$

$\implies ∠ACD = 106°$

Hence, meausre of ∠ACD= 106°

Note : Refer to the attachment for the required angle.

$\dagger \underline{\large \: \: {\frak{Points \: to \: remember : }}}$

• Angle is formed by two Ray's at one point.
• Angle is measured in degrees.
• Angle is drawn using protector.

Supplementary angles :

• Supplementary angles are the angles which are measured up to 180°
• For example angles (110° and 50°) these both angles are known as supplementary angles .

Complementary angles :

• Complementary angles are the angles which are measured up to 90°
• For example angles (30° and 40°) these both angles are known as complementary angles.