Question

Please give me right answer

Answer 1

Answer:

let ,

3rd digit is X

2nd digit is 8-X

1st digit is X/2

4th digit is X/2 × 8-X=(8x-x²)/2

According to question X/2 +(8-X)+X+(8x-x²)/2=12

=>(x+16-2x+2x+8x-x²)/2=12

=>16+9x-x²= 24

=>x²-9x+8=0

=>x²-8x-x+8=0

(x-8)(x-1)=0

x is 8 or 1

The digit is 4080

We can't taken 1 as 3rd digit because 1st digit is half of 3rd so .

in hindi:

तीसरा अंक X है

दूसरा अंक 8-X है

पहला अंक X / 2 है

चौथा अंक X / 2 × 8-X = (8x-x /) / 2 है

प्रश्न के अनुसार X / 2 + (8-X) + X + (8x-x /) / 2 = 12

=> (X + 16-2x + 2x + 8x-x²) / 2 = 12

=> 16 + 9x-x² = 24

=> X²-9x + 8 = 0

=> X²-8x-x + 8 = 0

(एक्स-8) (एक्स 1) = 0

x 8 या 1 है

अंक 4080 है

हम 1 को 3 अंक के रूप में नहीं ले सकते क्योंकि 1 अंक 3 का आधा है।