Question

please give me right answer ​

Answer 1

Step-by-step explanation:

1sol. ∆PQR is a right angled triangle

So,

h²= b²+p²

QR²= (10cm)²+(24cm)²

QR = √100cm²+576cm²

=√676cm²

= 26cm

2sol. Height of the tree till where it's broken=4m= perpendicular.

distance of the top touching the ground to the base = 3m = base

Now the broken part is the hypotenuse

Therefore,

H²= P²+B²

H² = (4m)²+(3m)²

H= √16m²+9m²

=√25m²

= 5m

So the original height of the tree = the length of tree till where its broken + the broken part

= 4m+5m= 9m