Question

please give me right answer and also formula Don't spam​

Answer 1

$\normalsize{\underline{\underline{\bf{Given:}}}}$

$\:\:\:\normalsize\bullet{\sf{\:Length\:of\:the\:floor\:is\:15\:m.}}$

$\:\:\:\normalsize\bullet{\sf{\:Breadth\:of\:the\:floor\:is\:12\:m.}}$

$\:\:\:\normalsize\bullet{\sf{\:Side\:of\:a\:square\:tile\:is\:30\:cm.}}$

$\normalsize{\underline{\underline{\bf{Need\:to\:find:}}}}$

$\:\:\:\normalsize\bullet{\sf{\:The\:number\:of\:tiles\: required\:to\:pave\:the\:floor.}}$

$\normalsize{\underline{\underline{\bf{Formulae\:to\:be\:used:}}}}$

$\:\:\:\normalsize\bullet\underline{\boxed{\sf{\:{Area}_{(rectangle)}=Length\times Breadth\:sq.units}}}$

$\:\:\:\normalsize\bullet\underline{\boxed{\sf{\:{Area}_{(square)}={(Side)}^{2}\:sq.units}}}$

$\:\:\:\normalsize\bullet\underline{\boxed{\sf{\:No.of.tiles\: required=\frac{Area\:of\:the\:floor}{Area\:of\:a\:tile}}}}$

$\normalsize{\underline{\underline{\bf{Solution:}}}}$

$\normalsize{\sf{1)\:Area\:of\:the\:floor:}}$

$\:\:\:\:\:\:\:\:\normalsize\longrightarrow{\sf{(Length\times Breadth)\:sq.units}}$

$\:\:\:\:\:\:\:\:\normalsize\longrightarrow{\sf{15\times 12}}$

$\:\:\:\:\:\:\:\:\normalsize\longrightarrow{\underline{\sf{180\:{m}^{2}\:(18000\:{cm}^{2})}}}$

$\normalsize{\sf{2)\:Area\:of\:a\:tile:}}$

$\:\:\:\:\:\:\:\:\normalsize\longrightarrow{\sf{{(Side)}^{2}\:sq.units}}$

$\:\:\:\:\:\:\:\:\normalsize\longrightarrow{\sf{{(30)^{2}}}}$

$\:\:\:\:\:\:\:\:\normalsize\longrightarrow{\underline{\sf{900\:{cm}^{2}}}}$

$\normalsize{\sf{3)\:No.of.tiles\: required:}}$

$\:\:\:\:\:\:\:\:\normalsize\longrightarrow{\sf{\frac{Area\:of\:the\:floor}{Area\:of\:a\:tile}}}$

$\:\:\:\:\:\:\:\:\normalsize\longrightarrow{\sf{\frac{180\cancel{00}}{9\cancel{00}}}}$

$\:\:\:\:\:\:\:\:\normalsize\longrightarrow{\sf{\frac{180}{9}=\red{\underline{\underline{20}}}}}$

$\normalsize{\underline{\underline{\bf{Final\:answer:}}}}$

$\:\:\:\normalsize\bullet{\sf{\:20\:tiles\:are\: required\:to\: pave\:the\:floor.}}$

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