Question

please give me solution of this problem
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Answer 1

Given :-

∠AOB = 90°

Clearly,

∠AOB = ∠AOE + ∠EOD + ∠DOB

∠AOB = (2x - 3)° + (2x + 4)° + (x + 9)°

Thus,

(2x - 3)° + (2x + 4)° + (x + 9)° = 90°

Solving this,

2x - 3 + 2x + 4 + x + 9 = 90

2x + 2x + x = 90 + 3 - 4 - 9

5x = 80

x = 80/5

x = 16

Now,

∠AOE = (2x - 3)°

= 2 × 16 - 3

= 29°

∠EOD = (2x + 4)°

= 2 × 16 + 4

= 36°

∠DOB = (x + 9)°

= 16 + 9

= 25°

ANSWER = 29°, 36°, 25°

Answer 2

Answer:

• angle AOB=90°
• angle AOB=angle AOE+angle EOD+angle DOB
• angle AOB=(2x-3)+(2x+4)+(x+9)
• 2x-3+2x+4+x+9=90
• 2x+2x+x=90+3-4-9
• 5x=80
• x=80/5
• x=16

so,angle AOE=2x-3

=2 (16)-3

=29°

angle EOD=2x+4

=2 (16)+4

=36°

angle DOB=x+9

=16+9

=25°

the angle are 29°,36°,25°

hope it helps you..

thankyou..