Question

please give me the answer​

Answer 1

Answer:

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Answer 2

Given :

• PQ // RS

To Find :

• Value of x , y and z .

Solution :

$\longmapsto\tt\bf{z=63^{\circ}\:(Corresponding\:Angles)}$

Now ,

As we know that Sum of all angles of a triangle is 180° . So ,

$\longmapsto\tt{63^{\circ}+55^{\circ}+x=180^{\circ}}$

$\longmapsto\tt{118^{\circ}+x=180^{\circ}}$

$\longmapsto\tt{x=180^{\circ}-118^{\circ}}$

$\longmapsto\tt\bf{x=62^{\circ}}$

Also ,

$\longmapsto\tt{x+y+z=180^{\circ}\:(Angles\:on\:one\:line)}$

$\longmapsto\tt{62^{\circ}+y+63^{\circ}=180^{\circ}}$

$\longmapsto\tt{125^{\circ}+y=180^{\circ}}$

$\longmapsto\tt{y=180^{\circ}-125^{\circ}}$

$\longmapsto\tt\bf{y=55^{\circ}}$

Therefore :

$\longmapsto\tt\bf{Value\:of\:x=62^{\circ}}$

$\longmapsto\tt\bf{Value\:of\:y=55^{\circ}}$

$\longmapsto\tt\bf{Value\:of\:z=63^{\circ}}$