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200
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According to the given condition let the length of CD and C′D′ be 2x and x respectievly.
C′D′CD=12
Area of a triangle=21×base×altitude
∴AreaofΔA′B′C′AreaofΔABC=21×21×x21×42×2x
=21×142×2=2184=14=(12)2
∴ The ratio of the areas of these similar triangles is the square of the ratio of the measures of the corresponding sides.
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