Math, asked by dubeybrahmananda, 7 months ago

Please give me the answer first? ​

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Answered by Truebrainlian9899
73

 \large \red{ \underline{ \underline{  \green{ \rm \: solution : }}}}

1 triangle :-

 \large  \:  \:  \:  \:  \:  \:  \:  \:  \rightarrow \orange{ \boxed{ \pink{ \rm \: angle \: sum \: property}}}

Angles of triangle ABC

  • 90°

  • 40°

\bigstar Sum of all interior angle of triangle = 180°

\rightarrow let finding angle be = x

\implies x + 90 ° + 40° = 180°

\implies x + 130° = 180°

  • On transposing the terms :

\implies x = 180° - 130°

\implies x = 50°

 \large  \therefore \blue{ \boxed{ \purple{ \rm \:3rd \:  \: angle =50 \degree }}}

_____________________________________________

2 triangle

 \large  \:  \:  \:  \:  \:  \:  \:  \:  \rightarrow \orange{ \boxed{ \pink{ \rm \: angle \: sum \: property}}}

Angles of triangle PQR

  • 35°

  • 30°

\bigstar Sum of all interior angle of triangle = 180°

\rightarrow let finding angle be = y

\implies y + 35° + 30° = 180°

\implies y + 65° = 180°

  • On transposing the terms :

\implies y = 180° - 65°

\implies y = 95°

 \large  \therefore \green{ \boxed{ \red{ \rm \:3rd \:  \: angle =95 \degree }}}

_____________________________________________

3 triangle

 \large  \:  \:  \:  \:  \:  \:  \:  \:  \rightarrow \orange{ \boxed{ \pink{ \rm \: angle \: sum \: property}}}

Angles of triangle LMN

  • 62°

  • 35°

\bigstar Sum of all interior angle of triangle = 180°

\rightarrow let finding angle be = z

\implies z + 35° + 62° = 180°

\implies z + 97° = 180°

  • On transposing the terms :

\implies z = 180° - 97°

\implies z = 83°

 \large  \therefore \purple{ \boxed{ \orange{ \rm \:3rd \:  \: angle =83 \degree }}}

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