Question

PLEASE GIVE ME THE ANSWER IF YOU KNOW ITS URGENT.

Locate $\sqrt{3}$ on the member line.

PLEASE GIVE ME THE ANSWER WITH STEP-BY-STEP EXPLAINATION.​

Answer 1

Answer:

⦁First construct thr BD of unit length perpendicular to OB.

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⦁Then apply the Pythagoras theorem $\rm{OD = \sqrt{(\sqrt{2})^{2} + 1^{2} = \sqrt{3}}}$.

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⦁We can locate $\rm{\sqrt{3}}$ on number line by using a compass.

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⦁We know that, O is the center and radius OD. Now let's draw an arc which intersects the number line at the point Q.

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⦁Therefore, now the point Q = $\rm{\sqrt{3}}$ on the number line.

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Refer the attachment for the diagram.