Question

Please give me the answer of 28 number

Answer 1

Answer:

$Tv \: tan \beta$

Explanation:

$As \: we \: know \:</p><p> that \: time \: of \: flight \: in \: motion \: </p><p>downward \: on \: incline \: plane \\ T = \frac{2usin \alpha }{gcos \beta } \\ R = \frac{2 {u}^{2}sin \alpha cos( \alpha - \beta ) }{g {cos}^{2} \beta } \\ Here \: in \: this \: figure \: \\ u = v \: \: \: \alpha = {90}^{0} \\ putting \: the \: value \: of \: \alpha \: and \: u \\ then \: T = \frac{2v}{gcos \beta } \\ let \: AB \: = R\\ R = \frac{2 {v}^{2}cos( {90}^{0} - \beta ) }{g {cos}^{2} \beta } \\ R = \frac{ 2v}{gcos \beta } \times \frac{vsin \beta }{cos \beta } \\ R = Tv \: tan \beta \\ AV = Tv \: tan \beta \\ Here \: we \: use \: \beta \: instead \: of \: theeta$

Hope it will help you......