Math, asked by khatrit432, 1 year ago

Please give me the answer of following question

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Answered by kundan567

0

sinP=RQ/PRPQ/PR
cosP =

Answered by narendrayadawa839

1

Answer:SIN P = QR/PR

COS P = PQ/PR

Step-by-step explanation: sin p = opposite /hypotenuse

Cos p = adjacent / hypotenuse

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